Also consider java.text.MessageFormat, which uses a related syntax having numeric argument indexes. For example, String aVariable = "of ponies"; String string = MessageFormat.format("A …

Apr 2, 2013 · String.contentEquals () compares the content of the String with the content of any CharSequence (available since Java 1.5). Saves you from having to turn your StringBuffer, etc …

7 String[] errorSoon = new String[n]; With n being how many strings it needs to hold. You can do that in the declaration, or do it without the String [] later on, so long as it's before you try use …

Apr 20, 2012 · Simply because Java7+ code using switch over string compiles to code assuming exactly that invariant property. So it can’t change in future versions and it’s even simpler to see …

I am trying to concatenate strings in Java. Why isn't this working? public class StackOverflowTest { public static void main (String args []) { int theNumber = 42; System.out.

Oct 16, 2013 · How to println a string and variable within the same parameters Asked 12 years ago Modified 2 years, 2 months ago Viewed 40k times

Once you have created a string you cannot later change that string object. Java uses pass-by-value, not pass-by-reference. When you assign a new value to s in your method it only …

String is a class, so a String variable is a reference. But it's a language intrinsic, in the sense that Java has special handling and syntax for it, which is why you can do things like your example.

StringBuilder.append () is preferable to plus when repeatedly adding to a string because every time you do string1 + string2 you're allocating a new string object and copying the characters …

Primitive question, but how do I format strings like this: "Step {1} of {2}" by substituting variables using Java? In C# it's easy.