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  1. Question #ca262 - Socratic

    It's not possible. Let's take a look at the skeleton equation: Li_3PO_4+CsI -> Li_3I+Cs_3PO_4 There is no way we can get this to follow the law of conservation of matter, because cesium is the only …

  2. Find the sum #sum_ (i=1)^6 (3i^2+4i+2)#? - Socratic

    sum_ (i=1)^6 (3i^2+4i+2)=369 As sum_ (i=1)^n1=n, sum_ (i=1)^ni= (n (n+1))/2 and sum_ (i=1)^ni^2= (n (n+1) (2n+1))/6 sum_ (i=1)^n (3i^2+4i+2) =3sum_ (i=1)^ni^2+4sum ...

  3. Question #b8278 - Socratic

    Perhaps if we rewrite this as: (3+2i)* (1-3i) then we mulitply 3 from the first paranthesis with the both constituents from the second. We do the same thing for the second constituent from the first …

  4. How do you evaluate (3a -9i +2ai +6)/ (a^2+9) + (3-9i+3i+9 ... - Socratic

    Aug 14, 2017 · Explanation: The first thing we notice with the two expression here is that the denominators are the same since #a^2+9=9+a^2#.

  5. Site Map - Angle between Vectors Questions and Videos | Socratic

    How do you use the definition of the scalar product, find the angles between the following pairs of vectors: - 4i + 5 j- k and 3i + 4j - k? What is the angle between the vectors #2bb (ul hat i)+2bb (ul hat …

  6. Question #d629b - Socratic

    b) I multiply the 2 brackets: #4*7-4*3i+7*3i-3*3i^2=28-12i+21i+9=37+9i# Answer link

  7. How do you evaluate the integral int ln (3x+4)? | Socratic

    Apr 15, 2018 · (3x+4)/3(ln(3x+4)-1)+C Let I= int ln(3x+4) dx N.B. Since I is an indefinite integral it cannot be "evaluated". Rather it can be expressed as a function of x plus an arbitrary constant. Let u=(3x+4) …

  8. How do you find \frac { - 3+ \sqrt { - 9} } { 6}? | Socratic

    Explanation: #"note that "sqrt (-9)=3i# #rArr (-3+3i)/6# #= (-3)/6+ (3i)/6=-1/2+1/2i# Answer link

  9. How do you combine like terms in #6- ( 4- 3i ) - ( - 2- 10i )#?

    Apr 6, 2017 · See the entire solution process below: First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly: 6 - 4 + 3i + 2 + 10i Next, group like …

  10. How do you evaluate # (19- 3i ) ( - 6- 14i )#? - Socratic

    -156-248i (19-3i)* (-6-14i)=-114+18i-266i-42=-156-248i