Voltage instead "regulates" how fast a motor can run: the maximum speed a motor can reach is the speed at which the motor generates a voltage (named "Counter-electromotive force") which is equal to the voltage it receives from battery (disregarding power losses and frictions for simplicity).
Voltage is the cause, current is the effect. So both sources provide a voltage on their terminals. In the voltage source the voltage on the output terminals has, or is intended to have, a constant value. Sometimes it's left to the internal resistance of the voltage source to determine what the final voltage will be, and sometimes the voltage at the terminals is measured and fed back to a ...
At a lower voltage, you need more current to provide the same power. So any device that is designed to provide the same power regardless of voltage will draw more current as the voltage drops.
And also if voltage is like gravitational potential energy, how does more voltage mean more current? And here our nice analogy breaks down. In this sense voltage is more like pressure in a water pipe.
According to Ohm's law, resistance varies directly with voltage You should read this the other way. Voltage varies directly with current. "R" is the constant of proportionality telling how much it varies. If I add in a resistor to a circuit, the voltage decreases. If you have a resistor in a circuit, with a current flowing through it, there will be a voltage dropped across the resistor (as ...
A current source can certainly have a voltage across it. If the voltage across a current source is zero, then it is not delivering or absorbing any power. However, if the voltage across the source is not zero, then it is either sourcing or sinking power into the rest of the circuit.
The reverse voltage is the voltage drop across the diode if the voltage at the cathode is more positive than the voltage at the anode (if you connect + to the cathode). This is usually much higher than the forward voltage. As with forward voltage, a current will flow if the connected voltage exceeds this value. This is called a "breakdown".
Some circuits need a negative voltage, so the positive side of a battery would be "ground". Some circuits need positive and negative voltages, in which case there could be two batteries, one with the negative side attached to ground, and the other with the positive side attached to ground. This works because voltages are relative.
Here when current flows in this circuit, due to ohm's some voltage has to be dropped across the internal resistance r, causing the output voltage, i.e, the voltage available at cell terminals across resistance R, to drop or increase as R is decreased or increased.
Most, or maybe all, topologies could end up outside of common mode voltage ranges at some specific time. What is important is to understand under what conditions will you be outside of the common-mode voltage range when designing a circuit, and if so will the op-amp you choose still suffice for your application?
